A & B & C by CodeChum Solution - AskTheCode

C++ program to find A & B & C | CodeChum Solution | C++ Programming

Problem:

I am the creator of the Truth Machine! It’s a machine that accepts 3 numbers, with each number having an accompanying bit position (since the numbers are going to be in binary). After successfully getting 1 bit from each number, the machine would then process the numbers to give us either a 1 or 0, depending on how truthful the bits processed are. I feel like no one in the world could possibly make something like it again!

Care to prove me wrong?

Input Format:

A single line containing six values: x1, x2, y1, y2, z1, and z2.

x1 represents A.

x2 represents bit position of A (starting 0 from right to left).

y1 represents B.

y2 represents bit position of B (starting 0 from right to left).

z1 represents C.

z2 represents bit position of C (starting 0 from right to left).

Output Format:

A single line containing either a 1 or 0.


Input Sample:

3 1 5 1 3 1


Output Sample:

0

Code:


// A & B & C by CodeChum
#include  <iostream>
#include <bits/stdc++.h>
using namespace std;

int size(char a[], int n){
	int len = 0;
	for (int i = 0; i < n; i++){
		if (a[i] != '0' && a[i] != '1'){
			break;
		}
		len++;
	}
	return len;
}

int main(){
	int x1, x2, y1, y2, z1, z2;
	cin >> x1 >> x2 >> y1 >> y2 >> z1 >> z2;
	char a[15], b[15], c[15];

	itoa(x1, a, 2);
	itoa(y1, b, 2);
	itoa(z1, c, 2);

	char first = a[size(a, 15)-x2-1];
	char second = b[size(b, 15)-y2-1];
	char third = c[size(c, 15)-z2-1];
	x1 = first;	y1 = second;	z1 = third;

	int result = (x1 & y1 & z1);
	cout << (char)result << endl;

	return 0;
}

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